Math, asked by rohitbhai1236, 10 months ago

X^2+5x-6 in completed square form.

Answers

Answered by ItzShinyQueen13
13

\huge\purple{\mathbb{AnsWer:}}

 ({x}^{2} + 5x - 6)^{2}  \\ =  {x}^{4} + 25 {x}^{2}   + 36 + 2 \times  {x}^{2} \times 5x  +  2 \times  5x \times ( - 6) + 2 \times ( - 6) \times  {x}^{2}  \\  =  {x}^{4} + 25 {x}^{2}  + 36 + 10 {x}^{3} - 60x - 12 {x}^{2}     \\ = {x}^{4}   + 10 {x}^{3} + 13 {x}^{2}   - 60x + 36

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Answered by Anonymous
4

Answer:

AnsWer:

\begin{lgathered}({x}^{2} + 5x - 6)^{2} \\ = {x}^{4} + 25 {x}^{2} + 36 + 2 \times {x}^{2} \times 5x + 2 \times 5x \times ( - 6) + 2 \times ( - 6) \times {x}^{2} \\ = {x}^{4} + 25 {x}^{2} + 36 + 10 {x}^{3} - 60x - 12 {x}^{2} \\ = {x}^{4} + 10 {x}^{3} + 13 {x}^{2} - 60x + 36\end{lgathered}

(x

2

+5x−6)

2

=x

4

+25x

2

+36+2×x

2

×5x+2×5x×(−6)+2×(−6)×x

2

=x

4

+25x

2

+36+10x

3

−60x−12x

2

=x

4

+10x

3

+13x

2

−60x+36

\begin{lgathered}\\\\\end{lgathered}

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