Question

x^2+√5x-60=0 solve the quadratic equation

Answer 1

${x}^{2} + \sqrt{5} x - 60 = 0 \\ \\ \\ {x}^{2} + 2 \times \frac{ \sqrt{5} }{2} \times x = 60 \\ \\ adding \: { \left( \frac{ \sqrt{5} }{2} \right)}^{2} both \: sides \\ \\ {x}^{2} + 2 \times \frac{ \sqrt{5} }{2} \times x + { \left( \: \frac{ \sqrt{5} }{2} \right)}^{2} = 60 + { \left( \: \frac{ \sqrt{5} }{2} \right)}^{2} \\ \\ { \left( \: x + \frac{ \sqrt{5} }{2} \right)}^{2} = \frac{240 + 5}{4} \\ \\ { \left( \: x + \frac{ \sqrt{5} }{2} \right)}^{2} = \frac{245}{4} \\ \\ First \: zero = \frac{ \sqrt{245} }{2} - \frac{ \sqrt{5} }{2} \Rightarrow \frac{7 \sqrt{5} - \sqrt{5} }{2} \Rightarrow \frac{6 \sqrt{5} }{2} \\ \qquad \qquad \; \Rightarrow 3 \sqrt{5} \\ \\ Second \: zero = - \frac{ \sqrt{245} }{2} - \frac{ \sqrt{5} }{2} \Rightarrow \frac{ - 7 \sqrt{5} - \sqrt{5} }{2} \Rightarrow \frac{ - 8 \sqrt{5} }{2} \\ \qquad \qquad \quad \Rightarrow - 4 \sqrt{5} \\ \\ Zeroes \: are \: \bold{3 \sqrt{5}} \: and \: \bold{ - 4 \sqrt{5}}$

Answer 2

Answer:

Step-by-step explanation: