x^2-(7+√3)X+6(1+√3)
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Solution:
The given Polynomial is x² - (7 + √3)x + 6(1+√3)
f(x) = x² - (7 + √3)x + 6(1+√3)
= x² - 7x - √3x + 6 + 6√3
= x(x - 7) - √3(x - 7)
= (x-7)(x-√3)
Therefore, Zeroes of Polynomial are (x-7)(x-√3).
Relationship between Zeroes:
Sum of Zeroes = -b/a
Product of Zeroes = c/a
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