Question

x^2+7x-18=0 in complete square​

Answer 1

${x}^{2} + 7x - 18 = 0 \\ {x}^{2} + (9 - 2)x - 18 = 0 \\ {x}^{2} + 9x - 2x - 18 = 0 \\ x(x + 9) + 2(x + 9) = 0 \\ (x + 9)(x + 2) = 0 \\ \\ x + 9 = 0 \\ x = 0 - 9 \\ x = - 9 \\ \\ x + 2 = 0 \\ x = 0 - 2 \\ x = - 2$

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