Question

x^(2)+7x=4 using quadratic formula

Answer 1

Equation : x² + 7x - 4 = 0

On comparing the equation with ( ax² + bx + c = 0 )

We get,
a = 1
b = 7
c = -4

Hence,
Discriminant = b² - 4ac

Putting the values,

Discriminant = ( 7 )² - 4( 1 × -4 )
=> 49 + 16
=> 65

$\mathbf{We \: \: know} \\ \\ \bold{x = \frac{ - b + \sqrt{discriminant} }{2a} } \: \: \: \: \: \: \: or \: \: \: \: \: \: \: \mathbf{x = \frac{ - b - \sqrt{discriminant} }{2a} }$
,

Putting the value of discriminant and b and a

x = [ - 7 + √65 ] / 2

Or

x = [ - 7 - √65 ] / 2

Answer 2

x^2 + 7x - 4 = 0
then ...a = 1 , b = 7 & c = -4

formula = - b +- √(b^2 - 4ac)/2a....

you can solve. ...by using this method....bro