x^2-7x-60=0 by complete square method
Answers
Step-by-step explanation:
Factoring x2+7x-60
The first term is, x2 its coefficient is 1 .
The middle term is, +7x its coefficient is 7 .
The last term, "the constant", is -60
Step-1 : Multiply the coefficient of the first term by the constant 1 • -60 = -60
Step-2 : Find two factors of -60 whose sum equals the coefficient of the middle term, which is 7 .
-60 + 1 = -59 -30 + 2 = -28 -20 + 3 = -17 -15 + 4 = -11 -12 + 5 = -7 -10 + 6 = -4 -6 + 10 = 4 -5 + 12 = 7 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -5 and 12
x2 - 5x + 12x - 60
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-5)
Add up the last 2 terms, pulling out common factors :
12 • (x-5)
Step-5 : Add up the four terms of step 4 :
(x+12) • (x-5)
Which is the desired factorization
Equation at the end of step 1 :
(x + 12) • (x - 5) = 0