Question

x^2+7x+999=0


Solve it
..


It's urgent....

because of my battery gonna be dead.
​

Answer 1

Answer:

The first term is, x2 its coefficient is 1 .

The middle term is, -10x its coefficient is -10 .

The last term, "the constant", is -999

Step-1 : Multiply the coefficient of the first term by the constant 1 • -999 = -999

Step-2 : Find two factors of -999 whose sum equals the coefficient of the middle term, which is -10 .

-999 + 1 = -998

-333 + 3 = -330

-111 + 9 = -102

-37 + 27 = -10 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -37 and 27

x2 - 37x + 27x - 999

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-37)

Add up the last 2 terms, pulling out common factors :

27 • (x-37)

Step-5 : Add up the four terms of step 4 :

(x+27) • (x-37)

Which is the desired factorization

Answer 2

Answer:

X^2+7x+999=0

Where,

a=1,b=7,c=999

$x = - b + - \sqrt{b {}^{2} - 4ac } \div 2a \\ x = - 7 + - \sqrt{49 - 4(1)(999)} \div 2 \\ x = - 7 + - \sqrt{49 - 3996} \\ x = - 7 + - \sqrt{ - 3947} \div 2 \\ x = - 7 + - \sqrt{3947} i \div 2(since \: i {}^{2} = - 1) \\ there \: are \: no \: actual \\\: factors \: for \: the \: \\above \: question \:$