Question

x^2+8x-48=0 use qaudratic formula and solve​

Answer 1

Answer:

$\huge\color{o}\boxed{\colorbox{yellow}{x = 4 ; x = -12}}$

Step-by-step explanation:

Equation:-

x² + 8x - 48 = 0

Quadratic formula:-

$\frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a}$

a = 1

b = 8

c = -48

Put value of a,b,c in the formula

$x = \frac{ - (8)± \sqrt{( {8}^{2}) } - 4(1)( - 48) }{2(1)}$

$= \frac{ - 8± \sqrt{64 + 192} }{2}$

$x = \frac{ - 8± \sqrt{256} }{2}$

$x = \frac{ - 8±16}{2}$

Now we have two values for x

$x = \frac{ - 8 + 16}{2} \: \: \: ,x = \frac{ - 8 - 16}{2}$

$x = \frac{ 8}{2} \: \: \: \: ,x = \frac{ - 24}{2}$

$x = 4 \: \: \: \: \: \: , \: x = - 12$