Question

x^2/98 - y^2/50 factorize​

Answer 1

Answer:

x^2/98-y^2 / 50

I/2(x^2/49-y^2/25)

I/2(x/7 +4/5) (x/7-4/5)

Answer 2

Answer:

$\frac{ {x}^{2} }{98} - \frac{ {y}^{2} }{50} \\ = \frac{1}{2} ( \frac{x}{ 7 } - \frac{y}{ 5} )( \frac{x}{7} + \frac{y}{ 5 } ) \\ =\frac{1}{2} ( \frac{x}{7 } - \frac{y}{5 } )( \frac{x}{7} + \frac{y}{5}) \\ = \frac{1}{2}( \frac{x}{7} - \frac{y}{5} )( \frac{x}{7} + \frac{y}{5} ) \\ = \frac{1}{2} \times \frac{1}{35} (5x - 7y)(5x + 7y) \\ = \frac{1}{70} (5x - 7y)(5x + 7y)$