Question

x^2+a^2/x^2-a^2 find the dy/DX=?​

Answer 1

Answer:

$y = \frac{x {}^{2} + a {}^{2} }{x {}^{2} - a {}^{2} }$

Using Division rule

$\frac{dy}{dx} = \frac{vu {}^{1} - uv {}^{1} }{v {}^{2} }$

$\frac{dy}{dx} = \frac{(x ^{2} -a {}^{2}). \frac{d(x {}^{2} + a {}^{2}) }{dx} - (x {}^{2} + a {}^{2}). \frac{d(x {}^{2} - a {}^{2}) }{dx} }{(x {}^{2} - a {}^{2}) {}^{2} }$

$\frac{dy}{dx} = \frac{(x {}^{2} - a {}^{2}).( 2x + a {}^{2} ) -(x {}^{2} + a {}^{2}).(2x + a {}^{2} ) }{(x {}^{2} - a {}^{2}) {}^{2} }$

Here " a" should not be Differnatated because it's a variable.

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