x^2+bc+11. the point (-1,8) lies on the graph of g. find the value of b
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Given eq x²+bc+11=0
It is also given that the point (-1,8) lies on the graph of the equation.
(-1)²+b(8)+11=0
1+8b+11 =0
8b = -12
b= -12/8
b = -3/2
b = -1.5
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AnSwEr
Given eq x²+bc+11 = 0
- It also given that the point (-1,8) lines on the graph of the equation.
- (-1)² + b(8) + 11 = 0
- 1+8b+11 = 0
- 8b = -12
- b = -12/8
- b = -3/2
- b = -1.6
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