(x+2) is a factor of p(x)=x³+x²+x+2,Examine the validity of the given statement.
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Answered by
3
Given, p(x) = x³ + x² + x + 2.
For (x + 2) to be a factor of p(x), the condition: p(–2) = 0; should be satisfied.
p(–2) = (–2)³ + (–2)² + (–2) + 2
= (–8) + (4) + (–2) + 2
= – 8 + 4 – 2 + 2
= –4 ≠ 0
Thus, (x + 2) is not a factor of the given polynomial.
therefore, the given statement is invalid.
For (x + 2) to be a factor of p(x), the condition: p(–2) = 0; should be satisfied.
p(–2) = (–2)³ + (–2)² + (–2) + 2
= (–8) + (4) + (–2) + 2
= – 8 + 4 – 2 + 2
= –4 ≠ 0
Thus, (x + 2) is not a factor of the given polynomial.
therefore, the given statement is invalid.
Answered by
2
Hi ,
It is given that ,
p( x ) = x³ + x² + x + 2 ,
Let g( x ) = x + 2 ,
The zero of g( x ) is -2 .
Then p( -2 ) = ( -2 )³ + ( -2 )² + ( -2 ) + 2
= -8 + 4 - 2 + 2
= - 10 + 6
= - 4
≠ 0
So , by the Factor Theorem ,
x + 2 is not a factor of p( x ).
I hope this helps you.
: )
It is given that ,
p( x ) = x³ + x² + x + 2 ,
Let g( x ) = x + 2 ,
The zero of g( x ) is -2 .
Then p( -2 ) = ( -2 )³ + ( -2 )² + ( -2 ) + 2
= -8 + 4 - 2 + 2
= - 10 + 6
= - 4
≠ 0
So , by the Factor Theorem ,
x + 2 is not a factor of p( x ).
I hope this helps you.
: )
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