Question

[x^2+(K+8)x+K) by (x-2)​

Answer 1

Answer:

we have to divide polynomial by x-2

first,put x-2=0

x=2

now, Put it in given polynomial,

we get (2)^2 +(k+8)(2)+k =0

4+2k+16+k=0

20+3k=0

k=-20/3

Answer 2

Step-by-step explanation:

hope it's helpfull to you