Question

x^2-kx+1=0 has two distinct roots ,then the value of k is different from .....
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Answer 1

Answer:

the value k is +2 and -2

Step-by-step explanation:

Answer 2

Answer:

k >±2

Step-by-step explanation:

x2-kx+1 = 0

a = 1, b = -k, c = 1.

b2-4ac >0

(-k)2 - 4(1)(1) >0

(-k2)-4>0

(-k)2>0 = 4

k >0 =±√4

k>0 = ±2

k = 0<±2

k>±2 = 0.

Verification:

If k=2, then b2-4ac= 2^2-4(1)(1)

= 4-4 = 0.

If k is greater than 0, like k = -3, then

b2-4ac = (-3)^2-4(1)(1)

= 9-4 = 5.