Question

X 2 + kx - 8 =0 ya varghsmikrnachi ek mul -4 aasel , tr k chi kimat kadha

Answer 1

Answer:

$\sf \longmapsto{x}^{2} + kx - 8 = 0 \\ \sf \longmapsto { (- 4)}^{2} + kx - 8 = 0 \\ \sf \longmapsto16 + kx - 8 = 0 \\ \sf \longmapsto \: kx + 8 = 0 \\ \sf \longmapsto \:k( - 4) + 8 = 0 \\ \sf \longmapsto - 4k + 8 = 0 \\ \sf \longmapsto - 4k = - 8 \\ \sf \longmapsto \: k = \frac{ - 8}{ - 4} \\ \sf \longmapsto \: k = 2$