Math, asked by rajkumaryaduvanshi21, 1 year ago

x^2+kx+k=0 has no solution then the value of k


rajkumaryaduvanshi21: full solution of my question

Answers

Answered by manojkmanu
1
k is equal to zero and is not
greater than zero

rajkumaryaduvanshi21: sir full solve
manojkmanu: sry i can only tell answers as it takes time
manojkmanu: and my answer is wrong
Answered by webstar0
16
x^2+kx+k=0

this equation has two distinct real solution.
now,
= b^2 -4ac = 0
if b = 1 , a = 1.

= k^2 - 4*(1)*k > 0
= k^2 -4k. > 0
= k (k-4) > 0
then ,
k >0 and k> 4

webstar0: answer is right
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