Question

x^2+kx+k=0 has two distnict real solutions the value of k

Answer 1

here it have two real roots

so b^2-4ac>0

k^2 - 4*1*k > 0

k^2 - 4k >0

K(k-4) > 0

k-4 > 0/4

k-4 > 0

k > 4

we can find its answer like this

Answer 2

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