Question

X=2 sin^2 theta, y=2 cos^2theta +1 then what is the value of x and y

Answer 1

Answer:

x=±π6+nπ for n∈Z

Explanation:

Using the identity cos(2x)=cos2(x)−sin2(x) we have

1=2cos2(x)−2sin2(x)

=2(cos2(x)−sin2(x))

=2cos(2x)

⇒cos(2x)=12

⇒2x=±π3+2nπ for n∈Z

∴x=±π6+nπ for n∈Z