Question

x + 2
Solve:
II
2x - 3
3x - 7
x + 3​

Answer 1

Answer:

$\frac{x + 2}{x + 3} = \frac{2x - 3}{3x - 7} \\ (x + 2)(3x - 7) = (2x - 3)(x + 3) \\ x(3x - 7) + 2(3x - 7) = x(2x - 3) + 3(2x - 3) \\ 3 {x}^{2} - 7x + 6x - 14 = 2 {x}^{2} - 3x + 6x - 9 \\ 3 {x}^{2} - 2 {x}^{2} - 7x + 3x + 6x - 6x = 14 - 9 \\ {x}^{2} - 4x = 5 \\ {x}^{2} - 4x - 5 = 0 \\ {x}^{2} - (5 - 1)x - 5 = 0 \\ {x}^{2} - 5x + x - 5 = 0 \\ x(x - 5) + 1(x - 5) = 0 \\ (x - 5)(x + 1) = 0 \\ x = 5 \: \: or \: \: x = - 1$

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Answer 2

Answer:

please make it brainliest answer x=5