Question

x^2+x+1=0 solve it.​

Answer 1

x²+x+1=0

2x²=1

x²=1/2

x=underroot0.5

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Answer 2

Answer:

${x}^{2} + x + 1 = 0 \\ comparing \: with \: a {x}^{2} + bx + c = 0 \\ a = 1 \: \: \: b = 1 \: \: \: \: c = 1 \\ x = - b + \ \frac{ \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = - 1 + \frac{ \sqrt{ {1}^{2} - 4 \times 1 \times 1 } }{2 \times 1} \\ x = - 1 + \frac{ \sqrt{1 - 4} }{2} \\ x = - 1 + \frac{ \sqrt{ - 3} }{2} \\ x = \frac{ - 2 + \sqrt{ - 3} }{2} \\ \\ or \: \\ \\ x = \frac{ - 2 - \sqrt{ - 3} }{2}$

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