x^2+(x+1)^2=85 factorizw the following
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X2+(X+1)2=85
We move all terms to the left:
X2+(X+1)2-(85)=0
We add all the numbers together, and all the variables
X^2+(X+1)2-85=0
We multiply parentheses
X^2+2X+2-85=0
We add all the numbers together, and all the variables
X^2+2X-83=0
a = 1; b = 2; c = -83;
Δ = b2-4ac
Δ = 22-4·1·(-83)
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
X1=−b−Δ√2a
X2=−b+Δ√2a
The end solution:
Δ−−√=336−−−√=16∗21−−−−−−√=16−−√∗21−−√=421−−√
X1=−b−Δ√2a=−(2)−421√2∗1=−2−421√2
X2=−b+Δ√2a=−(2)+421√2∗1=−2+421√2
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