(x-2)(x-1/2) expressions using formulae
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Answered by
0
Hello friends!!
Here is your answer :

Using identity :
( x + a) ( x + b) = x² + ( a + b)x + ab





Hope it helps you..
#Be Brainly
Here is your answer :
Using identity :
( x + a) ( x + b) = x² + ( a + b)x + ab
Hope it helps you..
#Be Brainly
Answered by
0
We can use this identity to solve this question :-
(x+a)(x+b)=x^2+(a+b)x+ab
(x-2) (x-1/2)=x^2+[-2+(-1/2)]x+(-2.-1/2)
=x^2+(-2-1/2)x+1
=x^2+(-4-1/2)x+1
=x^2-5/2x+1
(x+a)(x+b)=x^2+(a+b)x+ab
(x-2) (x-1/2)=x^2+[-2+(-1/2)]x+(-2.-1/2)
=x^2+(-2-1/2)x+1
=x^2+(-4-1/2)x+1
=x^2-5/2x+1
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