x+2/(x+1)²,Integrate the given function defined on proper domain w.r.t. x.
Answers
Answered by
10
HELLO DEAR,
GIVEN:-
∫(x + 2)/(x + 1)².dx
∫(x + 1 + 1)/(x + 1)².dx
∫(x + 1)/(x + 1)².dx + ∫1/(x + 1)².dx
∫dx/(x + 1) + ∫1/(x + 1)².dx
put (x + 1) = t
=> dx = dt
∫dt/t + ∫dt/t²
log|t| - 1/t + C.
put t = (x + 1)
log|x + 1| - 1/(x + 1) + C.
I HOPE IT'S HELP YOU DEAR,
THANKS
GIVEN:-
∫(x + 2)/(x + 1)².dx
∫(x + 1 + 1)/(x + 1)².dx
∫(x + 1)/(x + 1)².dx + ∫1/(x + 1)².dx
∫dx/(x + 1) + ∫1/(x + 1)².dx
put (x + 1) = t
=> dx = dt
∫dt/t + ∫dt/t²
log|t| - 1/t + C.
put t = (x + 1)
log|x + 1| - 1/(x + 1) + C.
I HOPE IT'S HELP YOU DEAR,
THANKS
Answered by
1
Dear Student,
Solution:
∫
Split the numerator and split both terms
= ∫
=∫
= ∫ + ∫
do integration now,1st term is 1/x form and second is 1/x² ,
do directly or apply substitution
= log (x+1) - 1/(x+1) +C
is the final answer.
Hope it helps you
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