Question

(x^2-x+1)^2-(x^2+x+1)^2​

Answer 1

Answer:

-4x(x^2-1)

Step-by-step explanation:

(x^2-x+1)^2-(x^2+x+1)^2

By identity of difference square

{a^2 - b^2 = (a+b)(a-b)}

where a = x^2 -x +1 , b = x^2 +x +1

So, the given equation will become

= [x^2 -x +1 + x^2 +x +1]×[x^2 -x +1-(x^2 +x +1)]

= (2x^2 +2)×(x^2 -x +1 - x^2 -x -1)

= (2x^2 +2)×(-2x)

= -4x^3 - 4x

If you just have to solve then this is your answer

Or otherwise,

= -4x(x^2-1)

= -4x(x+1)(x-1)

This is your answer

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