x+2(x-1)=5/2
free points guys answer it plz..
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Answered by
3
Answer:
Let’s start by using the FOIL method (First, Outer, Inner, Last) two expand the left side of the equation to get rid of the two sets of parentheses. Basically, on the left side of the equation we’ll just multiply each term in the first set of parentheses with each term in the second set of parentheses, then add everything together. The four terms are: 2x,1,x,and−5.
(2x+1)(x−5) = 2(x2−1)
2x·x+2x·(−5)+1·x+1·(−5) = 2(x2−1)
2x2−10x+x−5 = 2(x2−1)
2x2−9x−5
Answered by
10
Answer:
x+2(x−1)=2/5
x + 2x - 2 = \frac{5}{2}x+2x−2=2/5
2x + 4x - 4 = 52x+4x−4=5
6x = 96x=9
x = \frac{9}{6}x=6/9
x = \frac{3}{2}x=2/3
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