(x-2) (x+1) =(x-1)(x+3) check it is quadratic
Answers
Distribute
(−2)(+1)=(−1)(+3)
(+1)−2(+1)=(−1)(+3)
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Distribute
(+1)−2(+1)=(−1)(+3)
2+1−2(+1)=(−1)(+3)
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Multiply by 1
2+1−2(+1)=(−1)(+3)
2+−2(+1)=(−1)(+3)
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Distribute
2+−2(+1)=(−1)(+3)
2+−2−2=(−1)(+3)
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Combine like terms
2+−2−2=(−1)(+3)
2−−2=(−1)(+3)
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Distribute
2−−2=(−1)(+3)
2−−2=(+3)−1(+3)
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Distribute
2−−2=(+3)−1(+3)
2−−2=2+3−1(+3)
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Distribute
2−−2=2+3−1(+3)
2−−2=2+3−−3
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Combine like terms
2−−2=2+3−−3
2−−2=2+2−3
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Hello! Ur answer is below
Step-by-step explanation:
Given equation (x−2)(x+1)=(x−1)(x+3)
To find whether the given equation is a quadratic equation or not
Solution:-
⟹(x−2)(x+1)=(x−1)(x+3)
⟹x 2+x−2x−2=x 2 +3x−x−3
⟹x 2 −x 2+x−2x−3x+x−2+3=0
⟹−3x+1=0
This is not a quadratic equation as an equation of degree two is called a quadratic equation.
And, a polynomial when equated to zero or some value becomes an equation.