Question

(x-2)(x + 1) = (x - 1)(x+3)
check wether the following is a quadratic equation​

Answer 1

Answer:

${x}^{2} - x - 2 = {x}^{2} + 2x - 3$

Step-by-step explanation:

$(x - 2)(x + 1) = (x - 1)(x + 3)$

$x(x + 1) - 2(x + 1) = (x - 1)(x + 3)$

${x}^{2} + 1x - 2(x + 1) = (x - 1)(x + 3)$

${x}^{2} + x - 2(x + 1) = (x - 1)(x + 3)$

${x}^{2} + x - 2x - 2 = (x - 1)(x + 3)$

${x}^{2} - x - 2 = (x - 1)(x + 3)$

${x}^{2} - x - 2 = x(x + 3) - 1(x + 3)$

${x}^{2} - x - 2 = {x}^{2} + 3x - 1(x + 3)$

${x}^{2} - x - 2 = {x}^{2} + 3x - x - 3$

${x}^{2} - x - 2 = {x}^{2} + 2x - 3$

Answer 2

Step-by-step explanation:

it is not a quadratic equation