Question

(x-2) (x+3)^2<0 solve the following​

Answer 1

Answer:

We have,

x

2/3

+x

1/3

−2=0

Let x

1/3

=y

then,

x

2/3

+x

1/3

−2=0

y

2

+y−2=0

y

2

+(2−1)y−2=0

y

2

+2y−1y−2=0

y(y+2)−1(y+2)=0

(y+2)(y−1)=0

If y+2=0, y−1=0

y=−2, y=1

x

1/3

=−2, x

1/3

=1

x=(−2)

3

, x=1

3

x=−8, x=1