Question

(x+2) (x+3) -(x-1) (x-2) =7

Answer 1

Answer:

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Answer 2

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$(x + 2)(x + 3) - (x - 1)(x - 2) = 7 \\ ⇒({x}^{2} + 3x + 2x + 6) - ( {x}^{2} - 2x - x + 2) = 7 \\ ⇒{x}^{2} + 5x + 6 - {x }^{2} + 2x + x - 2 = 7 \\⇒ 8x + 4 = 7 \\⇒ 8x = 7 - 4 \\ ⇒ 8x = 3 \\ ⇒x= \frac{3}{8}$

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