(x+2)(x+3) +(x-3)(x-2)-2x(x+1)=0..
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Given equation:
(x+2)(x+3)+(x-3)(x-2)-2x(x+1)=0
=> x²+3x+2x+6+x²-2x-3x+6-2x²-2x=0
=> x²+5x+6+x²-5x+6-2x²-2x=0
=> x²+x²-2x²+5x-5x-2x+6+6=0
=> -2x+12=0
=> -2x=-12
=> x = (-12)/(-2)
=> x = 6
Therefore,
x=6
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