Question

(x+2) (x+3) +(x-3) (x-2) -2x(x+1)=0

Answer 1

x^2+3x+2x+6+x^2-2x-3x-6-2x^2-2x=0
2x^2+5x+6-6-5x-2x^2-2x=0
0=0
hence proved
LHS=RHS

Answer 2

Solution:-

=>(x+2) (x+3) + (x-3) (x-2) -2x(x+1) = 0

=>(x²+3x+2x+6 )+(x²-2x-3x+6)

-2x²-2x = 0

=> x²+5x+6 + x²-5x+6 - 2x² - 2x = 0

we can write it as

=> x²+x²-2x² +5x-5x -2x +6+6 = 0

=> 2x²-2x² - 2x + 12 = 0

=> - 2x + 12 = 0

=> - 2x = - 12

=> 2x = 12

=> x = 12/2

=> x = 6

i hope it helps you.