Math, asked by adhyan2614, 9 months ago

(x + 2)(x+3)+(x - 3)(x - 2) - 2x (x + 1) = 0​

Answers

Answered by adhikarimohit19
1

Answer:

x=6

Step-by-step explanation:

Answer:

x=6

Explanation:

Given equation:

(x+2)(x+3)+(x-3)(x-2)-2x(x+1)=0

=> x²+3x+2x+6+x²-2x-3x+6-2x²-2x=0

=> x²+5x+6+x²-5x+6-2x²-2x=0

=> x²+x²-2x²+5x-5x-2x+6+6=0

=> -2x+12=0

=> -2x=-12

=> x = (-12)/(-2)

=> x = 6

Therefore,

x=6

Answered by nilesh102
38

Solution:-

=>(x+2) (x+3) + (x-3) (x-2) -2x(x+1) = 0

=>(x²+3x+2x+6 )+(x²-2x-3x+6)

-2x²-2x = 0

=> x²+5x+6 + x²-5x+6 - 2x² - 2x = 0

we can write it as

=> x²+x²-2x² +5x-5x -2x +6+6 = 0

=> 2x²-2x² - 2x + 12 = 0

=> - 2x + 12 = 0

=> - 2x = - 12

=> 2x = 12

=> x = 12/2

=> x = 6

i hope it helps you.

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