Question

x^2 + x - 30 = 0 II. y^2 -12y + 35 = 0



a) if x > y
b) if x >= y
c) if x < y
d) if x <= y
e) if x = y or relationship between x and y can't be determined

Answer 1

Answer:

x ^2+x-30=0

x^2+6x-5x-30=0

by solving we get:

x= -6 or x= +5

y^2-12y+35=0

by solving we get:

y= 7 or y= 5

in both cases we get x=y=5.

.: the answer is e .