x^2-x^-6 and x^2+3x-18 common factor (x-a) find value of s
Answers
Answered by
1
facorise x² -x -6
x² -x -6
=x² -3x +2x -6
=x(x -3)+2(x -3)
=(x +2)(x -3)
again ,
factorise x²+3x -18
x² +3x -18
=x² +6x -3x -18
=x(x +6) -3(x + 16)
=(x -3)(x + 6)
now you can see that common factor of both expression is (x -3)
now , compare both (x - a) and (x -3)
then, a = 3
x² -x -6
=x² -3x +2x -6
=x(x -3)+2(x -3)
=(x +2)(x -3)
again ,
factorise x²+3x -18
x² +3x -18
=x² +6x -3x -18
=x(x +6) -3(x + 16)
=(x -3)(x + 6)
now you can see that common factor of both expression is (x -3)
now , compare both (x - a) and (x -3)
then, a = 3
Answered by
0
Answer:
Step-by-step explanation:
facorise x² -x -6
x² -x -6
=x² -3x +2x -6
=x(x -3)+2(x -3)
=(x +2)(x -3)
again ,
factorise x²+3x -18
x² +3x -18
=x² +6x -3x -18
=x(x +6) -3(x + 16)
=(x -3)(x + 6)
now you can see that common factor of both expression is (x -3)
now , compare both (x - a) and (x -3)
then, a = 3 .....
Similar questions