Question

(x + 2)(x – 6) = x2 + Bx + C. What are the values of B and C?

Answer 1

Answer:

Answer

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DiscriminantΔ=b2−4ac

Given:Discriminant =1

⇒b2−4ac=1 where a=6,b=b,c=2

⇒b2−4×6×2=1 

⇒b2−48=1 

⇒b2=1+48=49 

∴b=±7