x'2+x3– 132x) ÷ x (x – 11)
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x(x−11)
x
3
+x
2
−132x
=
x(x−11)
x(x
2
+x−132)
=
x−11
x(x+12)−11(x+12)
=
x−11
(x+12)(x−11)
=x+12
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