Question

x^2×y^2+23xy-420= whatttttttt???????​

Answer 1

Answer:

( x y + 35 ) ( x y - 12)

Step-by-step explanation:

Given ---> ( x² y² + 23 x y - 420 )

To find ---> Factorize the given

expression

Solution---> x² y² + 23 x y - 420

We factorize it by splitting the middle term. First we do prime factorization of 420

420 = 7 × 5 × 3 × 2 × 2

Now we make two numbers from these factors whose product is 420 and whose difference is 23

For this we can take 7 and 5 together and 2 , 2 and 3 together as follows

7 × 5 = 35

3 × 2 × 2 = 12

So the required numbers are 35 and 12

35 × 12 = 420

35 - 12 = 23

Now

x² y² + 23 x y - 420

=> x² y² + ( 35 - 12 ) xy - 420

=> x² y² + 35 xy - 12 xy - 420

=> x y ( x y + 35 ) - 12 ( xy + 35 )

=> ( x y + 35 ) ( x y - 12 )

Answer 2

Step-by-step explanation:

seee the picture .here. is your answer.

Have a good day