Question

x^2-y^2=7 and x-y =1, find the value of x

Answer 1

y=3
x=4
x=y+1
(1+y)²-y2-7=0
1+y2+2y-y2-7=0
y=3

Answer 2

$x - y = 1 \\ x {}^{2} - y { }^{2} = 7 \\ (x - y)(x + y) = 7 \\ x + y = 7 \: \\ on \: soving \: x = 4 \: and \: y = 3$