x+2/y+2=9/11, x+3/y+3=5/6 substitution
Answers
Answer:
x = 8, y = 9
The answer for this question is :-
= 11 (x+2) = 9 (y+2)
= 11x + 22 = 9y + 18 — eq.1
= 6 (x+3) = 5 (y+3)
= 6x + 18 = 5y + 15 — eq.2
We will keep aside both equations x and it's coefficient as we know in substitution method we have to keep any one x or y aside to find x or y value .
= 11x = 9y +18-22
= x = 9y-4
11
= 6x = 5y +15 -18
we will keep in equations form not in division form because we have to substitute x= 9y-4/11 .
= 6x - 5y = -3
Substitute x = 9y - 4 / 11 in eq . 2
= 6( 9y-4 ) - 5y = -3
( 11 )
= 54y-24 - 5y×11 = -3
11. 1 × 11
= 54y - 55y - 24 = -3 × 11
= -1y - 24 = -33
= -1y = -33 + 24
= -1y = -9
= 1y = 9
= y = 9
Substitute y = 9 in eq.1
= 11x - 9(9) = -4
= 11x - 81 = -4
= 11x = -4 + 81
= 11x = 77
= x = 77/11
= x = 7
So, x = 7 & y = 9
Please mark me as brainlest .
Answer:
x= 7
y = 9
Step-by-step explanation:
Firstly solve x+2/y+2= 9/11
By cross multiplication
=> 11(x + 2) = 9(y + 2)
=> 11x + 22 = 9y + 18
=> 11x + 9y = 18 - 22
=> 11x + 9y = - 4. ..........(1)
Now, solve x+3/y+3 = 5/6
By cross multiplication
=> 6(x + 3) = 5(y + 3)
=> 6x + 18 = 5y + 15
=> 6x - 5y = 15 - 18
=> 6x - 5y = -3. ...........(2)
Evaluating value of x From Eq.(2),
=> x = (-3 + 5y) / 6 .........(3)
Now, put value of x in Eq.(1)
=> 11*{(-3 + 5y) / 6} - 9y = -4
=> (-33 + 55y) / 6 - 9y = -4
=> (-33 + 55y - 54y) / 6 = -4
=> (-33 + y) / 6 = -4
=> -33 + y = -4*6
=> -33 + y = -24
=> y = -24+33
=> y = 9
Now, put value of y in Eq.(3)
=> x = {-3 + (5*9)} / 6
=> x = { -3 + 45} / 6
=> x = 42/6
=> x = 7
Hence, x = 7 and y = 9
Hope it will help you
Plz mark as brainliest