Math, asked by Suhaniwarsewarse, 9 months ago

x+2/y+2=9/11, x+3/y+3=5/6 substitution ​

Answers

Answered by suhaniwarse72
5

Answer:

x = 8, y = 9

The answer for this question is :-

= 11 (x+2) = 9 (y+2)

= 11x + 22 = 9y + 18 — eq.1

= 6 (x+3) = 5 (y+3)

= 6x + 18 = 5y + 15 — eq.2

We will keep aside both equations x and it's coefficient as we know in substitution method we have to keep any one x or y aside to find x or y value .

= 11x = 9y +18-22

= x = 9y-4

11

= 6x = 5y +15 -18

we will keep in equations form not in division form because we have to substitute x= 9y-4/11 .

= 6x - 5y = -3

Substitute x = 9y - 4 / 11 in eq . 2

= 6( 9y-4 ) - 5y = -3

( 11 )

= 54y-24 - 5y×11 = -3

11. 1 × 11

= 54y - 55y - 24 = -3 × 11

= -1y - 24 = -33

= -1y = -33 + 24

= -1y = -9

= 1y = 9

= y = 9

Substitute y = 9 in eq.1

= 11x - 9(9) = -4

= 11x - 81 = -4

= 11x = -4 + 81

= 11x = 77

= x = 77/11

= x = 7

So, x = 7 & y = 9

Please mark me as brainlest .

Answered by ruchisaini17
7

Answer:

x= 7

y = 9

Step-by-step explanation:

Firstly solve x+2/y+2= 9/11

By cross multiplication

=> 11(x + 2) = 9(y + 2)

=> 11x + 22 = 9y + 18

=> 11x + 9y = 18 - 22

=> 11x + 9y = - 4. ..........(1)

Now, solve x+3/y+3 = 5/6

By cross multiplication

=> 6(x + 3) = 5(y + 3)

=> 6x + 18 = 5y + 15

=> 6x - 5y = 15 - 18

=> 6x - 5y = -3. ...........(2)

Evaluating value of x From Eq.(2),

=> x = (-3 + 5y) / 6 .........(3)

Now, put value of x in Eq.(1)

=> 11*{(-3 + 5y) / 6} - 9y = -4

=> (-33 + 55y) / 6 - 9y = -4

=> (-33 + 55y - 54y) / 6 = -4

=> (-33 + y) / 6 = -4

=> -33 + y = -4*6

=> -33 + y = -24

=> y = -24+33

=> y = 9

Now, put value of y in Eq.(3)

=> x = {-3 + (5*9)} / 6

=> x = { -3 + 45} / 6

=> x = 42/6

=> x = 7

Hence, x = 7 and y = 9

Hope it will help you

Plz mark as brainliest

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