x^2+y^2+x+y+2xy factorise using grouping method
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Here's your answer...
x²+y²+x+y+2xy
= x²+2xy+y² + x+y
= (x+y)² + (x+y)
= (x+y)(x+y) + 1(x+y)
= (x+y)(x+y+1)
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Here's your answer...
x²+y²+x+y+2xy
= x²+2xy+y² + x+y
= (x+y)² + (x+y)
= (x+y)(x+y) + 1(x+y)
= (x+y)(x+y+1)
[0110100101]... More questions detected... [010110011110]
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//This is your friendly neighbourhood UnknownDude
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