Question

x^2+y^2+x+y+2xy solve by grouping

Answer 1

Simple solution :-

x² +y² +x+y +2xy

x²+y²+2xy +x+y

(x+y)² +x+y

(x+y)² +1(x+y)

(x+y) [(x+y) +1]

(x+y) [x+y+1]



I hope this will help you



-by ABHAY

Answer 2

Hope u like my process.
___________________
--> x² + y² + x + y +2xy

= (x² + y² +2xy) + x+y

= (x+y) ² + (x+y)
[since a² + b² +2ab =(a+b) ²]

= (x+y) {(x+y) + 1}

= (x + y) (x +y + 1) __answer__
_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_
Hope this is ur required simplified form

Proud to help you