Question

x^2+y^2+z^2-100/xy+yz+yx=-2

Answer 1

$= > {x}^{2} + {y}^{2} + {z}^{2} - 100 = - 2xy - 2yz - 2zx \\ = > {x}^{2} + {y}^{2} + {z}^{2} + 2xy + 2yz + zx = 100 \\ = > {(x + y + z)}^{2} = 100 \\ = > x + y + z = \sqrt{100 } \\ = > x + y + z = 10$

Answer 2

x +y+z=root 100
x+y+z=10
hope it helps prithu