English, asked by dhruvverma980, 1 year ago

(x^2+y^2-z^2)^2-(x^2-y^2+z^2)^2

Answers

Answered by ananya9151
0
(x^2 + y^2 - z^2)^2 - (x^2 - y^2 +z^2)^2
= (x^4 + y^4 - z^4) - (x^4 - y^4 + z^4)
= x^4 + y^4 - z^4 - x^4 + y^4 - z^4
= x^4 - x^4 + y^4 + y^4 - z^4 - z^4
= 2y^4 - 2z^4

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