Question

x^2 + y^2 + z^2 + 2xyz if x=2,y=-3,z=4​

Answer 1

Answer:

Given, x.=4 , y.=3,z z = - 2

=(4)^ 2 +(3)^ 2 +(-2)^ 2 +2*4*3*(-2)

=16+9+4-48

=-19

Now, x ^ 2 + y ^ 2 + z ^ 2 + 2XYZ

Answer 2

Answer:

Given- x=−2,y=3,z=1

So, x

3

+y

3

+z

3

−3xyz=(x+y+z)(x

2

+y

2

+z

2

−xy−yz−zx)

=(−2+3+1)((−2)

2

+(3)

2

+(1)

2

−(−6)−(−3)−(−2))

=(2)(4+9+1+6−3+2)

=(2)(19)