Question

ᴋɪꜱɪ ᴋᴏ ɪɴʙᴏx ᴄʜᴀʜɪʏᴇ?
20 ᴛʜᴀɴx + ꜰʟᴡ = ɪɴʙᴏx⚡
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QUESTION :-
Find two numbers such that one of them exceeds the other by 18 and their sum is 92.​

Answer 1

Solution :-

Let the number is x

The other number is x + 18

According to the given question -

➼ x + x + 18 = 92

➼ 2x + 18 = 92

➼ 2x = 92 - 18

➼ 2x = 74

➼ x = 74/2

➼ x = 37 .

Hence :-

The First Number = 37.

The Other = x + 18 = 37 + 18 = 55 .

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Answer 2

Answer:

Done....now inbox me......

Btw your answer-

Let the smaller number be x

So, the larger number is x+18

ATP,

x+(x+18)=92

x+x+18=92

x+x=92-18

2x=74

x=74/2

x=37

SMALLER NUMBER =37

LARGER NUMBER=37+18

=55

Hope it helps uh !!!!