X=2root6+5 then what is x+1/x
Deva150:
x =6
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i hope this will help you
let the 2root6 = a
1/x = (a-5)/{(a+5)(a-5)}. By reciprocal method
1/x = (a-5)/{(a*a)-(5*5)}
1/x = (a-5)/(a square - 25)
1/x = (2root6 -5)/{(4*6)-25}
1/x = 2root6 -5/(24-25) - 2root6-5/-1
1/x =-2root6+5
x+1/x =2root6+5+(-2root+5)
x+1/x =2root6 +5 -2root6+5
x+1/x =5+5
x+1/x =10
let the 2root6 = a
1/x = (a-5)/{(a+5)(a-5)}. By reciprocal method
1/x = (a-5)/{(a*a)-(5*5)}
1/x = (a-5)/(a square - 25)
1/x = (2root6 -5)/{(4*6)-25}
1/x = 2root6 -5/(24-25) - 2root6-5/-1
1/x =-2root6+5
x+1/x =2root6+5+(-2root+5)
x+1/x =2root6 +5 -2root6+5
x+1/x =5+5
x+1/x =10
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