x - 2y=-10; 3x - 5y= -12
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Solution:-
:-We have
=> x - 2y = -10 .......(i)eq
=> 3x - 5y = - 12 ........(ii)eq
Now using substitution method So take (i)eq
=> x - 2y = - 10
=> x = -10 + 2y .......(iii)eq
Put the value of x on (ii)eq
=> 3x - 5y = -12 ......(ii)eq
=>3( -10 + 2y ) - 5y = -12
=> -30 + 6y - 5y = -12
=> y = 30 - 12
=> y = 18
Now put the value of y on (iii)eq
=> x = - 10 + 2y .....(iii)eq
=> y = 18
=> x = - 10 + 2×18
=> x = - 10 + 36
=> x = 26
So answer x = 26 and y = 18
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