(x-2y)² - 5(x-2y) +6
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Step-by-step explanation:
let x-2y=t
so t^2-5t+6=0
t^2-2t-3t+6=0
(t-2)(t-3) =0
now t=2 and t=3
hence x-2y=2 and x-2y=3
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