Question

(x^2y^2+xy+1)ydy+(x^2y^2-xy+1)xdy=0

Answer 1

Step-by-step explanation:

The equation to solve is:

(x3y3+x2y2+xy+1)ydx+(x3y3−x2y2−xy+1)xdy=0

I tried putting xy=t but that just gave me this:

t3−t2−t+1t3+t2+t+1dt=dxx