Question

x+2y=3 and 2x-y=5 find x and y in substitution method.​

Answer 1

Step-by-step explanation:

x+2y=3

x=3-2y....(1)

2x-y=5...(2)

substituting eq(1) in eq(2).

2(3-2y)-y=5

6-4y-y=5

-5y=-1

y=1/5

substituting y=1/5 in eq(1)

x+2×1/5=3

x+2/5=3

x=3-2/5

x=15-2/5

x=13/5

Answer 2

Answer:

x + 2y = 3.......eqn1

2x - y = 5........eqn2

x + 2y = 3

2y = 3-x

y = 6 - 2x

sub y value in eqn2

2x - (6-2x) = 5

2x -6 +4x = 5

2x - 6 = 5

2x = 5 + 6

2x = 11

x = 11/2

sub x value in eqn1

$\frac{11}{2} + 2y = 3$

$\frac{11 + 4y}{2} = 3$

$11 + 4y = 6$

$4y = 6 - 11$

$4y = - 5$

$y = \frac{ - 5}{4}$